y^2-12y+48=0

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Solution for y^2-12y+48=0 equation: 



y^2-12y+48=0

a = 1; b = -12; c = +48;
Δ = b2-4ac
Δ = -122-4·1·48
Δ = -48
Delta is less than zero, so there is no solution for the equation

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